Calculate the osmotic pressure of 0.25M …
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Posted by Calvin Bhalerao 4 years, 1 month ago
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Sia ? 4 years, 1 month ago
T = {tex}{37^0}C{/tex} = 310 k
{tex}\pi = {\rm{ }}CRT{/tex} {tex} = \frac{n}{v}RT{/tex}
{tex} = 0.25 \times 0.083 \times 310{/tex}
= 6.43 bar.
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