A charged spherical conductor has surface …

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Posted by Neeraj Rawat 4 years, 2 months ago
- 3 answers
Aseem Mahajan 4 years, 2 months ago
$$4\pi r^2$$ = 4.4/0.084
Initial charge = 0.076 × $$4 \pi r^2$$
R = 2.04 cm
Initial charge = 0.076 × 4.4/0.084 = 3.98 C
Capacitance = $$4 \pi \epsilon_0 r$$ = 2.26 × 10-14 F
Harsh Shandilya 4 years, 2 months ago
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Premnath Arora 4 years, 2 months ago
0Thank You