A 44 mH inductor is connected …
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Posted by Uday Jadhav 4 years ago
- 3 answers
Aseem Mahajan 4 years ago
Irms = $$\sf \dfrac{V_{rms}}{X_L}$$
Irms = $$\sf \dfrac{220}{2\pi 50 \times 44 × 10^{-3}}$$
Irms = 1.65 A
Aseem Mahajan 4 years ago
Irms = $$\sf \dfrac{V_{rms}}{X_L}$$
Irms = $$\sf \dfrac{220}{2\pi 50 \times 44 × 10^{-3}}$$
Irms = 1.65 A
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Aseem Mahajan 4 years ago
Irms = $$\sf \dfrac{V_{rms}}{X_L}$$
Irms = $$\sf \dfrac{220}{2\pi 50 \times 44 × 10^{-3}}$$
Irms = 1.65 A
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