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Find the value of y for …

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Find the value of y for which the distance between the point P(2,-3),and Q(10,y) is 10 units

    • Posted by Sanju Singh 4 years, 1 month ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Caleb Narayan 4 years, 1 month ago

    The answer is 10^2=8^2+(3+y)^2 100=64+(9+y^2+6y) 36=9+y^2+6y 27=y^2+6y 27/6=y^2+y Answer 2.25 I think

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    Tannu Divakar 4 years, 1 month ago

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