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A park, in the shape of …

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A park, in the shape of a quadrilateral ABCD, has C=90°, AB=9 m, BC=12 m, CD=5 m and AD=8 cm. How much area does it occupy?

    • Posted by Oorja Jain 3 years ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Anuj Chauhan 3 years ago

    BD = 12cm ( by using Pythagoreas theorem) In right angle triangle bcd Area = 0.5 x base x height = 0.5 x 12 x 5 AreaI =30 cm sq Area II = traingle ABD =Using herons formula =Root s(s-a)(s-b)(s-c) =Root 15 x 7 x 6 x 2 = 6 root 35 =35.496 cm sq Total area = 30 +35.496 = 65.5 cm sq

    0Thank You

    Sejal Tiwari 3 years ago

    65.5 m square

    3Thank You

    ANSWER
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