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If two positive integers m and n can be expressed as m=x2y5 and n=x3y2 where x and y are prime numbers , then HCF(m,n)=

Posted by O M Anirudh 4 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Gunjan Kumari 4 years, 3 months ago

Common in both HCF(m,n)x²y²

0Thank You

Snehil Gupta 4 years, 3 months ago

m=x*x*y*y*y*y*y n=x*x*x*y*y taking common from m and n then we get, x*x*y*y=x^2y^2

3Thank You

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