A man of 60 kg weight …
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A man of 60 kg weight is standing at rest on a platform. He jumps up vertically a distance of 1 m and the platform at the same instant moves horizontally forward with the result that the man lands 1 meter behind the point on the platfrom from where the took the jump the total work done by the man at the instant he lands is
Posted by Rahul Parul 3 years, 2 months ago
- 2 answers
Gaurav Maurya 3 years, 2 months ago
Work done = F . S
=Fscostheeta (where Theeta=0°)
W = M × g × s
= 60 × 10 × 1
= 600 J
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Gaurav Maurya 3 years, 2 months ago
4Thank You