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If cot A=15/8 find sinA, cosA, …

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If cot A=15/8 find sinA, cosA, cosecA

Posted by Neeraj Kataria 4 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Vivek Pathak 4 years, 2 months ago

cotA=b/p Given,b/p=15/8 By applying Pythagoras theorem we get, P^2+b^2=h^2 8^2+15^2=h^2 54+225=h^2 h=√64+225 therefore, H=17 SinA=p/h =8/17 CosA=b/h=15/17 and, CosecA=h/b=17/15 Hope you will like this answer

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Nitin Tripathi 4 years, 2 months ago

Given that:- cot A=15/8 And we know that:- cot A=b/p So that, base is 15 & perpendicular is 8 and by the Pythagoras theorem we find 17 as a hypotenuse. Hence, •sin A=p/h=8/17 •cos A=b/h=15/17 •cosec A=h/p=17/8 Hope you understand this very simple way.

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Mandeep Kumar 4 years, 2 months ago

Cot A=b/p Sin A=p/h CosA=b/h CosecA=h/p Given Cot A=15/8 b=15 p=8 We find h from Pythagoras theorm h²=b²+p² h=17 So,SinA=8/17,Cos=15/17 and Cosec=17/8

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