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P(t)=2+t+2t²-t³

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P(t)=2+t+2t²-t³
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Shreya Chawla 3 years, 1 month ago

P(t)=2+t+2t2-t3 then the values of p(0),p(1),p(2) are respectively p(t)=2+t+2t2-t3 p(0)=2+0+2*0*2-0*3 =2 p(1)=2+1+2*1*2-1*3 =4 p(2)=2+2+2*2*2-2*3 =9
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