Two trains A and B of …
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Two trains A and B of length 400 m each are moving on two parallel tracks with a
uniform speed of 72 km h–1
in the same direction, with A ahead of B. The driver of
B decides to overtake A and accelerates by 1 m s–2
. If after 50 s, the guard of B just
brushes past the driver of A, what was the original distance between them?
Posted by Lohitha Harish 3 years, 3 months ago
- 1 answers
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Sia ? 3 years, 3 months ago
Given that,
uA = uB =72 kmh−1 = 72 × 185 = 20 ms−1
Using the relations, s = ut + 1/2 at2, we get
SB = uBt + 1/2 at2 = 20 × 50 + 1/2 × 1 × (50)2
SB = 1000 + 1250 = 2250m
Also, let SA be the distance covered by the train A, then SA = uA × t
= 20 × 50 = 1000 m
Original distance between the two trains
= SB − SA
= 2250 − 1000 = 1250 m
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