1-i in square root

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1-i in square root

Posted by Malika Singh 3 years, 3 months ago

CBSE > Class 11 > Mathematics

1 answers

Komal Bhanndari 3 years, 2 months ago

1-i = (x+iy)^2 1-i = x- (iy)^2= x^2- y^2+ 2xyi x^2- y^2 = 1 and 2xy = -1 (x^2+y^2)^2 = (x^2- y^2)^2 + (2xy)^2 (x^2+ y^2)^2 =1 - 1 =0

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