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Range of f(x) = sin[x] and …

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Range of f(x) = sin[x] and x belongs to -π/4,π/4
  • 2 answers

Cheeku 18 3 years, 3 months ago

0 when x>0 or x=0 -Sin(1) when x<0 So range ={(-sin1),0}

God Father 3 years, 4 months ago

π\4
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