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Find 2 consecutive positive integers ,sum …

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Find 2 consecutive positive integers ,sum of whose squares is 925.
  • 1 answers

Sia ? 4 years, 2 months ago

let first integer be x
then its consecutive integer be (x+1)
according to question
x^2 + (x+1)^2 = 925
2x^2 + 2x - 924 = 0
x^2 + x - 462 = 0
x = -1 +- √1 + 4*462 / 2
x = -1 +- 43/2
x = -1 + 43 /2 = 21
x = -1 - 43/2 = -22
x = 21 , -22

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