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In R.S. Agrawal Book's page no …

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In R.S. Agrawal Book's page no 227 Que:20 - In the given figure,AB||ED and BC||EF. Show that angle ABC= angle DEF.

    • Posted by Bhoomi Dubey 4 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Sia ? 4 years, 6 months ago

    Given BA || ED and BC || EF.
    To show {tex}\angle{/tex}ABC = {tex}\angle{/tex}DEF.
    Construction Draw a ray EP opposite to ray ED. 

    Proof In the figure, BA || ED or BA || DP
    {tex}\therefore{/tex}  {tex}\angle{/tex}ABP = {tex}\angle{/tex}EPC [corresponding angles]
    {tex}\Rightarrow{/tex} {tex}\angle{/tex}ABC = {tex}\angle{/tex}EPC ....(i)
    Again, BC || EF or PC || EF
    {tex}\therefore{/tex} {tex}\angle{/tex}DEF = {tex}\angle{/tex}EPC [corresponding angles] ....(ii)
    From eqs.(i) and (ii),
    {tex}\angle{/tex}ABC = {tex}\angle{/tex}DEF

    3Thank You

    ANSWER
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