5x²-6x-2 solution

5x^2 -6x-2 Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a(x-x1)(x-x2), where x1 and x2 are the solutions of the quadratic equation ax^2+bx+c=0. 5x^2-6x-2=0 All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: -b± sqrt{b^{2}-4ac} / 2a. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction. x=-(-6)± sqrt-6^{2} / 2×5 Square -6. x=-(-6)± sqrt{36-4) / 2×5 Multiply -4 times 5. x=-(-6)± sqrt(36-2) / 2×5 and so on ...................................... And after solving this whole u will get : x= 3- sqrt{19} / 5 Factor the original expression using ax^{2}+bx+c=a(x-x1)(x-x2). Substitute 3+sqrt{19}/ 5 for x1 and 3-sqrt{19}/ 5 3-sqrt{19}/ 5 for x2. The 2 zeros are ● 3+sqrt{19}/ 5 ● 3-sqrt{19}/ 5 And u can convert it into factors