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TanQ/1-cotQ + cotQ/1-tanQ = 1+ tanQ …

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TanQ/1-cotQ + cotQ/1-tanQ = 1+ tanQ + cotQ
  • 1 answers

Ishwar Deshmukh 4 years, 2 months ago

$$ L H S = =1−tanxcotx​+1−cotxtanx​ 1−tanxcotx​+(1−cotx)(−tanx)tanx(−tanx)​ 1−tanxcotx​−1−tanxtan2x​ 1−tanxcotx−tan2x​=tanx(1−tanx)1−tan3x​ (1−tanx)(tanx)(1−tanx)(1+tanx+tan2x)​ 1+cotx+tanx= R H S  Hence proved.
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