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The vapour pressure of water is 12.3kPa at 300k. Calculate the vapour pressure of 1 molar solution of a solute in it.

Posted by Rishav Raj 3 years, 4 months ago

CBSE > Class 12 > Chemistry

1 answers

Kabita Sharma 3 years, 4 months ago

Molar mass of water is=18 g/mol No. Of Mole present in 1000g of water 1000/18=55.56 mol Mole fraction(Xi)= amount of constituent in moles/Total amount of constituents in a mixture in moles Xi=1/1+55.6 = 0.0177 As we know that relative lowering in vapour pressure is equal to the mole fraction of the solute. p1-p\p=X 12.3-p/12.3=0.0177 p=12.08

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