Give possible expression for the lenght …
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Preeti Dabral 3 years, 3 months ago
I have replaced x with y,
Answer as follows:
{tex}{\text{Area : }}35{y^2} + 13y - 12{/tex}
The expression {tex}35{y^2} + 13y - 12{/tex} can also be written as, 35y2 + 28y - 15y - 12
= {tex}35{y^2} + 28y - 15y - 12 = 7y\left( {5y + 4} \right) - 3\left( {5y + 4} \right){/tex}
{tex}= \left( {7y - 3} \right)\left( {5y + 4} \right){/tex}
Therefore, we can conclude that a possible expression for the length and breadth of a rectangle of area {tex}35{y^2} + 13y - 12{/tex} is Length = 7y - 3 and Breadth = 5y + 4
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