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N2 gas is bubbled through water …

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N2 gas is bubbled through water at 293 k how many millimoles of N2 gas would dissolved in 1 litre of water? Assume that N2 exerts a partial pressure of 0.987 bar. Given that Henry's law constant for N2 at 293 k is 76.48 k bar.

Posted by Tushar Hooda 3 years, 4 months ago

CBSE > Class 12 > Chemistry

1 answers

Badal Barasiya 3 years, 4 months ago

According to Henry's law, p N 2 =K H .X N 2 ⇒x N 2 = 76800 0.987 =1.29×10 −5 Moles of water in 1L= 18 1000 =55.56 Let us take the moles of nitrogen as n Total moles =n+55.56 ∴ x N 2 = n+55.56 n =1.29×10 −5 ⇒n(1−1.29×10 −5 )−55.56×1.29×10 −5 =0 ⇒n=0.7×10 −3 =0.7 milimoles

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