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The displacement of particle is x=3t …

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The displacement of particle is x=3t square -2t+5. Calculate the velocity and acceleration at t= 2 seconds.

    • Posted by Nandini Nagda 3 years, 4 months ago

    CBSE > Class 11 > Physics
    • 4 answers

    Harmanpreet Kaur 3 years, 4 months ago

    X=3t^2-2t+5. We will solve it by differentiation. V=d(3t^2-2t+5)/dt V=d(3t^2)/dt-d(2t)/dt+d(5)/dt V=6t-2+0 At t=2,V=6×2-2 V=10m/s Now a=d(V)/dt a=d(6t-2)/dt a=d(6t)/dt -d(2)/dt a=6-0 a=6×t^o At t=2,a=6m/s2

    0Thank You

    Amritansh‌ Pandey 3 years, 4 months ago

    Acceleration -12

    0Thank You

    Amritansh‌ Pandey 3 years, 4 months ago

    6t-2

    0Thank You

    Abc ... 3 years, 4 months ago

    10 m/s

    0Thank You

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