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How much time would a police man take to catch a thief if the velocity of police man is 20m/s and the acceleration of thief is 1m/s square and the distance between them is 150m

Posted by Bhargav Navin 3 years, 4 months ago

CBSE > Class 11 > Physics

3 answers

Preeti Dabral 3 years, 4 months ago

Just suppose both Policeman and thief are running in the same direction.

Given :-

Acceleration of Thief = 1 m/s²

Velocity of Police = 20 m/s

Using the first equation of motion :-

v = u + at

20 = 1 × t

t = 20 s

Note :-

1. The velocity of Policeman must be more than that of thief otherwise the thief will never be caught.

2. When both will have equal velocity then also thief can never be caught.

3. Relative Velocity of theif w.r.t police will be lesser than that of relative velocity of police w.r.t thief.

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Bhargav Navin 3 years, 4 months ago

Thank you for the reply of my question but we cannot get the answer by only supposing them in the same direction as it would create more doubts in our mind

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Bhargav Navin 3 years, 4 months ago

Not actually I think we should choose thief as the frame of reference and then assume that thief is in rest and watching the police then we will get that the distance between police man and thief is becoming large and large as there is the acceleration of thief and police man has constant velocity so that there would be two answers means that police man and thief meet two times first when police man suddenly speed up then it will be the first meeting during g running and finally on that position where police man will be caught

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