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Find the number of terms in the finite AP 3,6,9....111.

Posted by Krish Kadia 4 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 4 years, 3 months ago

So, first term = a = 3
Common difference = d = 3
Last term = Tn = 111
Let number of terms be n.
Now, Tn = a + (n-1)d
So, 111 = 3 + (n-1)×3
So, 108 = 3×(n-1)
So, 108/3 = n-1
So, n-1 = 36
So, n = 37
Thus, number if terms is 37.

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CBSE > Class 10 > Mathematics