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(1+1/tan^2A) (1+1/cot^2A) = 1/cos^2-cos^4

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(1+1/tan^2A) (1+1/cot^2A) = 1/cos^2-cos^4

Posted by Gurwishwash Singh 4 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Preeti Dabral 4 years, 3 months ago

LHS
=(1+1/tan²A).(1+1/cot²A)
=(1+cot²A).(1+tan²A)
=cosec²A.sec²A
=1/(sin²A.cos²A)
=1/{(1-cos²A)cos²A}
=1/(cos²A-cos⁴A) = RHS(Proved)

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CBSE > Class 10 > Mathematics