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Preeti Dabral 2 years, 10 months ago
Let the A.P be
The first term is 'a'
The common difference is 'd'.
The nth term of the A.P is given by,d)
The (m+n)th term of A.P is-1)d%3Da%2B(m%2Bn-1)d)
The (m-n)th term of A.P is-1)d%3Da%2B(m-n-1)d)
The sum of (m+n)th and (m-n)th term of an A.P is given by,
Now, m th term of A.P is given by,
Twice of m th term isd))
From (1),
Therefore, The sum of (m+n)th and (m-n)th term of an A.P is equal to twice the mth term
1Thank You