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Find the zeroes of cubic polynomial …

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Find the zeroes of cubic polynomial 3x^2-5x^2-11x-3 when it is given that product of any two of its zeroes is -1

Posted by Sridhar Govindaraj 4 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Deepak Sharma 4 years, 3 months ago

First of all type the correct expression Sridhar. I think expression is 3x^3-5x^2-11x-3 Let P(x) = 3x^3-5x^2-11x-3 P(-1) = 0 hence (x+1) is a factor of P(x) Divide P(x)=3x^3-5x^2-11x-3 by (x+1) and we get the quotient is 3x^2-8x-3 Now factories the quotient by using factorisation method 3x^2-8x-3 3x^2-9x+1x-3 3x(x-3)+1(x-3) (x-3)(3x+1) Now, x-3=0 >>> x=3 3x+1=0 >>> x=-1/3 Hence all three zeroes of the cubic polynomial P(x) is -1, 3 and -1/3

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