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If α and β are the zeros of the polynomial f(x)=2x2+5x+k satisfying the relation α2+β2+αβ=21/4, find the value of k.

Posted by Vanshika Saxena 4 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Arsalanur Rahman 4 years, 4 months ago

Nahi malum?

2Thank You

Sappy Bakshi 4 years, 4 months ago

As f(x)=2x2+5x+k So alpha+beeta=-5/2 as -co eff of x /coeff of xsquare So alpha*beeta=k/2 constant/ co eff of x square So now your equation is - (alpha +beta)square + alpha*beeta =21/4 So by replacing values (-5/2)square+k/2=21/4 25/4+k/2=21/4 Transpose 25/4 to rhs k/2=21/4-25/4 k/2=-4/4 k=-4/4*2 k=-2 I hope your doubt is cleared best of luck for future

2Thank You

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CBSE > Class 10 > Mathematics