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What is the hcf of 13 and 72 by Euclid's theorem

Posted by B Vedhu 4 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Denish Kotia 4 years, 4 months ago

Using Euclid's Division Lemma a=bq+r Where, 0<_ r<b a=72, b=13 72=13×5+7 a=13, b=7 13=7×1+6 a=7, b=6 7=6×1+1 a=6, b=1 6=1×6+0 Therefore, HCF of 72 and 13 is 1.

3Thank You

Shashank Sivaram 4 years, 4 months ago

The HCF (72, 13) by Euclid's algorithm/theorem is: a = bq + r (0<_r<b) 72 = 13 x 5 + 7 (a = 72, b = 13) 13 = 7 x 1 + 6 (a = 13, b = 7) 7 = 6 x 1 + 1 (a = 7, b = 6) 6 = 1 x 6 + 0 (a = 6, b = 1) So, HCF (72, 13) is 1.

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