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A lift starts from the top …

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A lift starts from the top of a mine shaft and descends with a constant speed of 10 m/s. 4 s later a boy throws a stone vertically upwards from the top of the shaft with a speed of 30 m/s. If stone hits the lift at a distance x below the shaft write the value of Š / (in m) [Take: g = 10 m/s?] (Give value of 20/6 = 49)

Posted by Manikya Kishore Varshney 4 years, 7 months ago

CBSE > Class 12 > Physics

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Sia ? 4 years, 7 months ago

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