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Without finding cubes, factorise (2x-5y)^3 +(5y-3z)^3 …

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Without finding cubes, factorise (2x-5y)^3 +(5y-3z)^3 +(3z-2x)^3
  • 2 answers

Ayaan Ansari 8 years ago

Same

Eva Sony 1 year, 6 months ago

(2x-5y)^3+(5y-3z)^3+(3z-2x)^3=0 =3(2x-5y)(5y-3z)(3z-2x) =90xyz-54xz^2-225zy^2+135z-60x^2y+36x^2z+150xy^2-90xz
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