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Find the zeroes of p(x)= 2x2-x-6 …

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Find the zeroes of p(x)= 2x2-x-6 and verify the relationship of zeroes with these co-efficients

Posted by Aanchal Ahalawat 4 years, 5 months ago

Adithya Dev A 4 years, 5 months ago

2x^2 - x - 6 = 0 (S = -1, P = -12, No. = -4, 3). 2x^2 - 4x + 3x - 6 = 0. 2x (x - 2) + 3 (x - 2) = 0. (2x + 3) (x - 2) = 0. Therefore, x = -3/2, 2.//

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