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Two charges of equal magnitudes kept at a distance r exert a force F on each other. If the charges are halved and distance between them is doubled, what is the new force acting on each charge
Posted by Rachita T 4 years, 5 months ago
- 5 answers
Anurag Saral 4 years, 5 months ago
Force when magnitude of charge is same
F=q^2/4(pi)(Eo)r^2
if charges are halved and distance is doubled then
F=q^2/64(pi)(Eo)r^2
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Nidhi Bharti 4 years, 5 months ago
1Thank You