No products in the cart.

Solve the following systems of equations …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Solve the following systems of equations 11x+15x+23=0 7x-2y-20 =0
  • 1 answers

Adithya Dev A 4 years, 5 months ago

11x + 15y = -23 ---- (1) ////// 7x - 2y = 20 ---- (2). Take equation (2). Thus, x = 20 + 2y / 7// ---- (A). Equating (A) to (1), we get :- 11 (20 + 2y / 7) + 15y = -23 => 220 + 22y / 7 + 15y = -23 => 220 + 22y + 105y = -161 => 127y = -161 - 220 => 127y = -381 => y = -3// Therefore, x = 20 + 2y / 7 = 20 - 6 / 7 = 14 / 7 = 2//
http://mycbseguide.com/examin8/

Related Questions

Venu Gopal has twice
  • 0 answers
X-y=5
  • 1 answers
sin60° cos 30°+ cos60° sin 30°
  • 2 answers
Prove that root 8 is an irration number
  • 2 answers
(A + B )²
  • 1 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App