Solve the following systems of equations …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Aditi Malasi 4 years, 6 months ago
- 1 answers
Related Questions
Posted by Parinith Gowda Ms 2 months, 1 week ago
- 0 answers
Posted by Parinith Gowda Ms 2 months, 1 week ago
- 1 answers
Posted by Vanshika Bhatnagar 1 year, 3 months ago
- 2 answers
Posted by Lakshay Kumar 11 months, 3 weeks ago
- 0 answers
Posted by Sahil Sahil 1 year, 3 months ago
- 2 answers
Posted by Hari Anand 5 months ago
- 0 answers
Posted by Kanika . 3 months ago
- 1 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Sia ? 4 years, 6 months ago
11x + 15y = -23 ---- (1) ////// 7x - 2y = 20 ---- (2). Take equation (2). Thus, x = 20 + 2y / 7// ---- (A). Equating (A) to (1), we get :- 11 (20 + 2y / 7) + 15y = -23 => 220 + 22y / 7 + 15y = -23 => 220 + 22y + 105y = -161 => 127y = -161 - 220 => 127y = -381 => y = -3// Therefore, x = 20 + 2y / 7 = 20 - 6 / 7 = 14 / 7 = 2
0Thank You