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For any positive integer is n, …

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For any positive integer is n, prove that n³-n divisible by 6
  • 1 answers

Simran Panwar 4 years, 5 months ago

Out of three (n – 1), n, (n + 1) one must be even, so a is divisible by 2. 2. (n – 1) , n, (n + 1) are consecutive integers thus as proved a must be divisible by 3. Thus, n³ – n is divisible by 6 for any positive integer n.
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