Exercise 4.2 question no: 1.(ii) question …

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Sia ? 4 years, 7 months ago
2x2 + x − 6
Completing the square,
{tex}\Rightarrow{/tex} x2 + {tex}\frac x2{/tex} − 3 = 0
{tex}\Rightarrow{/tex} x2 + {tex}\frac x2{/tex} + {tex}\frac 1{16}{/tex} − {tex}\frac 1{16}{/tex} − 3 = 0
{tex}\Rightarrow{/tex} (x + {tex}\frac 14{/tex})2 − {tex}\frac {49}{16}{/tex} = 0
{tex}\Rightarrow{/tex} (x + {tex}\frac 14{/tex} − {tex}\frac 74{/tex})(x + {tex}\frac 14{/tex} + {tex}\frac 74{/tex}) = 0
{tex}\Rightarrow{/tex} (x − {tex}\frac 32{/tex}) (x + 2) = 0
{tex}\Rightarrow{/tex} x = {tex}\frac 32{/tex}, −2
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