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√5 is a irrational

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√5 is a irrational
  • 5 answers

Anuradha Chaudhary 4 years, 7 months ago

We prove by contradiction method. Let assume that √5 is rational. √5=p/q ---eq......1 P and q are co prime integer with common factor 1. Squaring both side equation 1 5=p²/q² :. q²=p²/5 eq...2 It means p² have factor 5 so p would also have sector 5. p=5x squaring both side p²=25x² Puting this value of p² in equation 2 q²=25x²/5 q²=5x² q²/5=x² This means q² have factor 5. But our assumption says p and q have common factor 1. So our assumption was wrong √5 is irrational number.

Mamta ... 4 years, 7 months ago

yes √ 5 is an irrational no.

Ayan Patel 4 years, 7 months ago

Let 5​ be a rational number. then it must be in form of  qp​  where,  q=0     ( p and q are co-prime) 5​=qp​ 5​×q=p Suaring on both sides, 5q2=p2           --------------(1) p2 is divisible by 5. So, p is divisible by 5. p=5c Suaring on both sides, p2=25c2         --------------(2) Put p2 in eqn.(1) 5q2=25(c)2 q2=5c2 So, q is divisible by 5. . Thus p and q have a common factor of 5. So, there is a contradiction as per our assumption. We have assumed p and q are co-prime but here they a common factor of 5. The above statement contradicts our assumption. Therefore, 5​ is an irrational number.

Ayan Patel 4 years, 7 months ago

√5 =p/q

Ayan Patel 4 years, 7 months ago

Let us assume that√5 is rational
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