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Cos thetha=0.6, show that (5sin thetha-3tan …

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Cos thetha=0.6, show that (5sin thetha-3tan thetha) =0.
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Simran Rathore 4 years, 7 months ago

Given=cosA=0.6 CosA=B/H 0.6=B/H 6/10=B/H Base=6 Hypo.=10then by using pythagoras theorem Perpendicular =8 Prove: 5sinA-3tanA=0 5×P/H-3×P/B=0 5×8/10-3×8/6=0 4-4=0 0=0 Hence proved
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