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KH for N2 is 1×10^-5 atm …

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KH for N2 is 1×10^-5 atm at 298 k. The mole fraction of N2 in air is 0.8. The number of moles of N2 from air that dissolves in 10 moles water at 298 k and 5 atm pressure are.... My challenge those who will answer this question they are genius Thanks
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Mahima Pattanayak 3 years, 8 months ago

Total pressure is 5 atm. The mole fraction of nitrogen is 0.8.  Hence,the partial pressure of nitrogen=PT​×X=0.8×5=4 atm  According to Henry's law, P=KX x is the mole fraction K is the henry's law constant P is the pressure in atm. Substitute values in the above expression. X=1×105atm4 atm​=4×10−5=10n​ n=4.0×10−4mol

Sumit Kumar 3 years, 8 months ago

KH for N2 1×10^5 hai bhai log sorry
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