Factorise:1 - 64a³ - 12a + …
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Sia ? 3 years, 6 months ago
We have,
1 - 64a3 - 12a + 48a2 = (1)3 - (4a)3 - 3(1)(4a)(1 - 4a)
= (1 - 4a)3 [{tex}\because{/tex} a3 - b3 - 3ab(a - b) = (a - b)3]
= (1 - 4a)(1 - 4a)(1 - 4a)
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