If a=2+root 3 , then find …
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Posted by Poonam Nandiwale 3 years, 6 months ago
- 4 answers
Safiya 7 3 years, 6 months ago
a= 2+√3
1/a= 1/ 2+√3
Conjugate of 2+√3 is 2-√3
=1/2+√3 x 2-√3/2-√3
= 2-√3/2²-(√3)²
= 2-√3/4-3
1/a = 2-√3
a-1/a = 2+√3-(2-√3)
= 2+√3-2+√3
= √3+√3=2√3
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Arhaan Mallik 3 years, 6 months ago
1Thank You