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If sinA=3/4 then find the value …

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If sinA=3/4 then find the value of secA

Posted by Priyanshi Yadav 4 years, 6 months ago

CBSE > Class 10 > Mathematics

5 answers

Tanvi @1201 4 years, 6 months ago

Sec=4 by root 7

Tanishq Singh 4 years, 6 months ago

Sin A = 3/4 =perpendicular /base P=3 H=4 We can find tha base by pythagoras theorem in triangle ABC BA²=AC²-BC² BA²=4²-3² BA²=16-9 BA²=7 BA=√7 SecA = hypotenuse /base SecA=4/√7

It'S Krishna 4 years, 6 months ago

Diya soni you copied my answer

Divya Soni 4 years, 6 months ago

Sin A = 3/4 =perpendicular /base P=3 H=4 We can find tha base by pythagoras theorem in triangle ABC BA²=AC²-BC² BA²=4²-3² BA²=16-9 BA²=7 BA=√7 SecA = hypotenuse /base SecA=4/√7

It'S Krishna 4 years, 6 months ago

Sin A = 3/4 =perpendicular /base P=3 H=4 We can find tha base by pythagoras theorem in triangle ABC BA²=AC²-BC² BA²=4²-3² BA²=16-9 BA²=7 BA=√7 SecA = hypotenuse /base SecA=4/√7

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