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Ch 6 ex 4

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Ch 6 ex 4

    • Posted by Chandan Singh Yadav 3 years, 7 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Aryan Sharma 3 years, 6 months ago

    Here, we need to draw a line AB parallel to line PQ, through point M as shown in Fig. 6.25. Now, AB || PQ and PQ || RS Therefore, AB || RS (Why?) Now, ∠ QXM + ∠ XMB = 180° (AB || PQ, Interior angles on the same side of the transversal XM) But ∠ QXM = 135° So, 135° + ∠ XMB = 180° Therefore, ∠ XMB = 45° (1) Now, ∠ BMY = ∠ MYR (AB || RS, Alternate angles) Therefore, ∠ BMY = 40° (2) Adding (1) and (2), you get ∠ XMB + ∠ BMY = 45° + 40° That is, ∠ XMY = 85°

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