Two resistor of 10Ω and 15Ω …

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Two resistor of 10Ω and 15Ω are connected in series to a battery of 6v . How can the values of current passing through them be compared?

Posted by Om Kumar 4 years, 9 months ago

CBSE > Class 10 > Science

4 answers

Taufeeque Sifat 4 years, 9 months ago

Well the resistors are connected in a series connection then the current would be same for them. You need to just find the equivalent resistance of them and calculate the current. Equivalent resistance = (10 + 15) Ω = 25 Ω So the current would be I = V/R = 6 V/25 Ω = .24 A So the current through both the resistors will be 0.24 A.

1Thank You

Anurag Singh 4 years, 9 months ago

Correct answer is 0.24 ampere

1Thank You

Siya Singhal 4 years, 9 months ago

R1=10ohm,R2=15ohm,v=6v Connected in series are the R=R1+R2=10+15=25ohm V=IR I=v/R I=6/25 I=1/2.4ampere

1Thank You

Suhani Rana 4 years, 9 months ago

R1=10 ohm R2=5 ohm V=6 v In series, Therefore R1+R2=R 10+5=15 ohm New R =15 ohm Since, V=IR I= V/R I= 6/15 I=2/5 I = 0.4A ans. Current is passing through them is 0.4 ampere

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