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For θ=30°, verify that : Sin2θ=2tanθ/1+tan²θ

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For θ=30°, verify that : Sin2θ=2tanθ/1+tan²θ
  • 2 answers

Ankita Kharkwal 4 years, 6 months ago

From RHS ≈2tan theta /1+tan² theta ≈2tan30/1+tan²30 ≈2×1/√3/1+(1/√3)² ≈2/√3/4/3 ≈6/4√3 ≈6/√3/12 ≈√3/2 From LHS Sin2 theta Sin2(30) Sin60 √3/2 LHS =RHS Hence proved

Ayushi Varshney 4 years, 6 months ago

sin2*30°=2tan30°/1+tan30°*tan30°
http://mycbseguide.com/examin8/

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