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1/a+b+c=1/a+1/b+1/c .....solve for x

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1/a+b+c=1/a+1/b+1/c .....solve for x
  • 5 answers

Abhijot Bedi 4 years, 6 months ago

No the question is right

Saliha Tahir 4 years, 6 months ago

Take lcm 1/x(a+b+x)=1/ab X a+b-x/x(a+b+x)=a+b/ab X cut by x -a+b/x(a+b+x)=a+b/ab Now-a+b cut by a+b -1/x(a+b+x)=1/ab Cross multiple -ab=x(a+b+x) -ab=ax+bx + x^2 -ab=x(a+b)+x^2 Take ab to right side X^2+(a+b)x+ab=0 By quardic formula -b+/-√b²-4ac/2a (You can see formula from book) Now but values -a-b +/-√(a+b)²+4*1*ab/2 Put identity of (a+b)² -a-b+/- √a²+b²+2ab-4ac/2 -a-b+/-√a² +b²-2ab/2 -a-b +/-√(a-b)²/2 Now take +ve -a-b+a-b/2 A cut by a -2b/2 X= -b Take -ve -a-b-a+b/2 B cut by b -2a/2 X= -a So the values for X = -a , -b

Saliha Tahir 4 years, 6 months ago

If ur question is like this then it is ur ans.... 1/a+b+x=1/a+1/b+1/x Now take 1/x to left side Then , 1/a+b+x-1/x=1/a+1/b Take lcmon both side

Saliha Tahir 4 years, 6 months ago

Because if you don't have x in ur question then how u can solve it for x I think the ques can be like this .... 1/a+b+x=1/a+1/b+1/x

Saliha Tahir 4 years, 6 months ago

Hii I think ur question is wrong
http://mycbseguide.com/examin8/

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