No products in the cart.

A ray of light while travels …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

A ray of light while travels from denser to rarer medium undergoes total internal reflection. Derive expression for critical angle in terms of speed of light in two mediums.
  • 1 answers

बेबि बीच 4 years, 7 months ago

Let a ray from medium 1 (rarer) to enter medium 2(denser) such that refractive index occurs, now, Using snell's law, n1 sin i = n2 sin r where i is angle lf incidence and r is angle of refraction. Now since total internal reflection is occuring here, angle r = 90° Using this in snells law we get, n1 sin i = n2 ic = critical angle (ic) here, sin ic=(n2/n1) since n(refractive index) = speed of ray in vaccum / speed in medium, Therefore, sin ic= (c/v1)/(c/v2) = v2/v1 Therefore critical angle = v2/v1
http://mycbseguide.com/examin8/

Related Questions

Derivation of ohm's law class 12
  • 0 answers
what us current
  • 2 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App