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Calculate emf cu/cu2+(0.25)//fe3+(0.005M)/fe2+(0.1M)/pt

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Calculate emf cu/cu2+(0.25)//fe3+(0.005M)/fe2+(0.1M)/pt

Posted by Dr P.Jothi 4 years, 6 months ago

CBSE > Class 12 > Chemistry

2 answers

Bhawna Chaudhary 4 years, 6 months ago

At anode:- Cu =Cu^2+ +2e- ---A At cathode:-Fe^3+= Fe^2+ +1e- ----B For balancing e- multiply eqnB by 2. E¤cell = E¤ cathode -E¤ anode For this E¤Cu+/cu and E¤Fe3+/Fe2+ will be provided in the ques by that you can calculate E¤cell. After that apply nernst eqn.

Sanu ? 4 years, 6 months ago

Dr. hokar bhi 12 mai padh rhi ho ??

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