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Mg + Cu+2 → Mg +2 …

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Mg + Cu+2 → Mg +2 + Cu has E0 cell = 2.71 V . Calculate ∆G0 .

Posted by Sneha Das 3 years, 9 months ago

CBSE > Class 12 > Chemistry

1 answers

Tejal Arora 3 years, 9 months ago

For the cell reaction, Mg(s)+Cu 2 +(aq)→Mg 2 +(aq)+Cu(s); E o cell=+2⋅71V The change in the standard Gibbs free energy is given as: ΔrG o =−nFE o cell=−2×96500×2.71=−523030 Jmol −1

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