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.1 mole of an ideal gas at 5OOK expands isothermally until its volume becomes 3 times.Find amount of work done and heat absorbed in the process? (Use R=8.3 Jmol K^(1) and in 3=1 .1 )

Posted by Karamjit Kaur 3 years, 9 months ago

CBSE > Class 11 > Physics

1 answers

Nikki Singhal 3 years, 8 months ago

Given: Number of moles of gas = 1 Temperature = 500K To find: The amount of work done and heat absorbed in the process. Solution: Work done in an isothermal process is: W = nRT ln(V2/ V1) W = 1 X 8.3 X 500 ln(3V/ V) W = 4150 ln3 W = 4150 X 1.1 W = 4565 J Heat absorbed in the process = -4565 J because the work done by the gas will go into the heat absorbed by the surrounding. The work done by the gas in the process is 4565 J and the heat absorbed by the surrounding is -4565 J.

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