Find the area of an isosceles …
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Posted by Sanjeev Kumar 8 years, 4 months ago
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Poulami Dasgupta 8 years, 4 months ago
Area of an isosceles triangle = {tex}{\sqrt3\over 2}(side)\ ^ 2{/tex}
= {tex}{\sqrt3\over2}(15)\ ^ 2{/tex}
={tex}225\sqrt3\over2{/tex}
={tex}112.5\sqrt3{/tex}
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